F(-3)=2x^2+4x+1

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Solution for F(-3)=2x^2+4x+1 equation: 



(-3)=2F^2+4F+1

We move all terms to the left:

(-3)-(2F^2+4F+1)=0

We add all the numbers together, and all the variables

-(2F^2+4F+1)-3=0

We get rid of parentheses

-2F^2-4F-1-3=0

We add all the numbers together, and all the variables

-2F^2-4F-4=0

a = -2; b = -4; c = -4;
Δ = b2-4ac
Δ = -42-4·(-2)·(-4)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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